x^2+16x+51=0

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Solution for x^2+16x+51=0 equation:


Simplifying
x2 + 16x + 51 = 0

Reorder the terms:
51 + 16x + x2 = 0

Solving
51 + 16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-51' to each side of the equation.
51 + 16x + -51 + x2 = 0 + -51

Reorder the terms:
51 + -51 + 16x + x2 = 0 + -51

Combine like terms: 51 + -51 = 0
0 + 16x + x2 = 0 + -51
16x + x2 = 0 + -51

Combine like terms: 0 + -51 = -51
16x + x2 = -51

The x term is 16x.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16x + 64 + x2 = -51 + 64

Reorder the terms:
64 + 16x + x2 = -51 + 64

Combine like terms: -51 + 64 = 13
64 + 16x + x2 = 13

Factor a perfect square on the left side:
(x + 8)(x + 8) = 13

Calculate the square root of the right side: 3.605551275

Break this problem into two subproblems by setting 
(x + 8) equal to 3.605551275 and -3.605551275.

Subproblem 1

x + 8 = 3.605551275 Simplifying x + 8 = 3.605551275 Reorder the terms: 8 + x = 3.605551275 Solving 8 + x = 3.605551275 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = 3.605551275 + -8 Combine like terms: 8 + -8 = 0 0 + x = 3.605551275 + -8 x = 3.605551275 + -8 Combine like terms: 3.605551275 + -8 = -4.394448725 x = -4.394448725 Simplifying x = -4.394448725

Subproblem 2

x + 8 = -3.605551275 Simplifying x + 8 = -3.605551275 Reorder the terms: 8 + x = -3.605551275 Solving 8 + x = -3.605551275 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = -3.605551275 + -8 Combine like terms: 8 + -8 = 0 0 + x = -3.605551275 + -8 x = -3.605551275 + -8 Combine like terms: -3.605551275 + -8 = -11.605551275 x = -11.605551275 Simplifying x = -11.605551275

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-4.394448725, -11.605551275}

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